Write iqr_outliers(nums) returning the values outside [Q1 − 1.5·IQR, Q3 + 1.5·IQR] (use np.percentile), in original order.
iqr_outliers([10, 12, 12, 13, 12, 11, 14, 13, 15, 102]) → [102]
iqr_outliers([1, 2, 3, 4]) → []
Submit runs 3 tests, including hidden edge cases.
Run your code to see the output here.